Han Wang net worth
Quick answer
Han Wang's estimated net worth is $22.4M (range $15.68M – $33.6M) as of 2026. Han Wang is CTO at Upfort. Upfort valuation.
Han Wang is CTO at Upfort (YC S17). Independent Entrepreneurial Check model estimate from public YC data.
At a glance
- Company status: Active
- Background: Chinese, Asian
- Education: Master's in Computer Science from University of California, Berkeley
- Region: United States of America
- Industries: B2B, Security
- Team size: 38
- Website: https://www.upfort.com
Who is Han Wang?
Han Wang is a founder at Upfort, which participated in Y Combinator's Summer 2017 batch.
Highlights:
- Y Combinator (S17)
- University of California, Berkeley
- MIT Media Lab
Background
Heritage labels inferred from name patterns only — not verified. Heritage/background labels may be inferred and are not verified identity documents.
About Upfort
Upfort is a leading platform for cyber security and insurance that provides holistic protection from evolving cyber threats. Founded in 2017 to expand global access to cyber resilience, Upfort makes cyber risk easy to manage and simple to insure. Upfort delivers turnkey security proven to proactively mitigate risk and comprehensive cyber insurance from leading insurers. With proprietary data and intelligent...
FAQ: Han Wang net worth and Upfort valuation
What is Han Wang's net worth?
Han Wang's estimated net worth is $22.4M (range $15.68M – $33.6M) as of 2026. Han Wang is CTO at Upfort. Entrepreneurial Check publishes an independent model-based estimate from public company and role data. Not verified net worth, and Entrepreneurial Check is not affiliated with Y Combinator or the profiled companies.
What is Upfort valuation?
Upfort's estimated valuation on Entrepreneurial Check is $80.0M. That valuation, or a disclosed round when one is public, is the source for the paper-wealth estimate. Independent model output — not a verified appraisal or official mark.
What is Han Wang's role?
Han Wang is CTO at Upfort, a Y Combinator-backed startup (batch S17).